Subtraction with Regrouping: 583 − 47

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 583 − 47?

Answer

583 − 47 =
536

With regrouping: 1 borrow — from the tens

583 − 47 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
7+10
5 8(was 8, now 7)3 (was 3, now 13)
−47
536

Column by column: 583 − 47

  • Ones: 3 is less than 7 — borrow 1 ten: tens 8 → 7; 13 − 7 = 6 — write 6.
  • Tens: after borrowing, 7; 7 − 4 = 3 — write 3.
  • Hundreds: nothing to subtract — write 5.

583 − 47 = 536

Second check: 583 − 536 = 47

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Recalculate with different values ↑

Column subtractions of 47

ExampleDifference
286 − 47239
300 − 47253
315 − 47268
354 − 47307
395 − 47348
400 − 47353
423 − 47376
449 − 47402
500 − 47453
532 − 47485
583 − 47536
600 − 47553
625 − 47578
694 − 47647
700 − 47653
800 − 47753
900 − 47853
1,000 − 47953
2,000 − 471,953
5,000 − 474,953

FAQ

What is 583 − 47?

583 − 47 = 536

How do you check that 583 − 47 = 536?

Add the difference and the subtrahend: 536 + 47 = 583. Getting the minuend back means the difference is right.

How many times do you borrow in 583 − 47?

1 borrow: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

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