Subtraction with Regrouping: 406 − 58

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 406 − 58?

Answer

406 − 58 =
348

With regrouping across a zero: 2 borrows — there are no tens to borrow from, so 1 hundred becomes 10 tens, and 1 ten goes to the ones

406 − 58 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
39+10
4(was 4, now 3)0(was 0, now 9)6 (was 6, now 16)
−58
348

Column by column: 406 − 58

  • Ones: 6 is less than 8 — borrow 1 hundred across the zero: hundreds 4 → 3, tens 0 → 9; 16 − 8 = 8 — write 8.
  • Tens: after borrowing, 9; 9 − 5 = 4 — write 4.
  • Hundreds: after borrowing, 3; nothing to subtract — write 3.

406 − 58 = 348

Second check: 406 − 348 = 58

Similar examples to practise

See Also

FAQ

What is 406 − 58?

406 − 58 = 348

How do you check that 406 − 58 = 348?

Add the difference and the subtrahend: 348 + 58 = 406. Getting the minuend back means the difference is right.

How many times do you borrow in 406 − 58?

2 borrows: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

Why does 0 become 9 when borrowing in 406 − 58?

The zero has nothing to lend, so it first borrows 1 from its left neighbour and becomes 10; then it lends 1 to the column on its right and keeps 9.