Subtraction with Regrouping: 1,000 − 47

Subtraction with Regrouping Calculator
Minuend
Subtrahend

What is 1,000 − 47?

Answer

1,000 − 47 =
953

With regrouping across a zero: 3 borrows — there are no hundreds or tens to borrow from, so 1 thousand becomes 10 hundreds, and 1 ten goes to the ones

1,000 − 47 in a column. Above the columns: the values after borrowing — a crossed-out digit is replaced by the number above it; +10 marks a column that received a borrowed ten.
099+10
1(was 1, now 0)0(was 0, now 9)0(was 0, now 9)0 (was 0, now 10)
−47
953

Column by column: 1,000 − 47

  • Ones: 0 is less than 7 — borrow 1 thousand across the zero: thousands 1 → 0, hundreds 0 → 9, tens 0 → 9; 10 − 7 = 3 — write 3.
  • Tens: after borrowing, 9; 9 − 4 = 5 — write 5.
  • Hundreds: after borrowing, 9; nothing to subtract — write 9.
  • Thousands: after borrowing, 0 — a leading zero is not written.

1,000 − 47 = 953

Second check: 1,000 − 953 = 47

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Recalculate with different values ↑

Column subtractions of 47

ExampleDifference
300 − 47253
315 − 47268
354 − 47307
395 − 47348
400 − 47353
423 − 47376
449 − 47402
500 − 47453
532 − 47485
583 − 47536
600 − 47553
625 − 47578
694 − 47647
700 − 47653
800 − 47753
900 − 47853
1,000 − 47953
2,000 − 471,953
5,000 − 474,953
10,000 − 479,953

FAQ

What is 1,000 − 47?

1,000 − 47 = 953

How do you check that 1,000 − 47 = 953?

Add the difference and the subtrahend: 953 + 47 = 1,000. Getting the minuend back means the difference is right.

How many times do you borrow in 1,000 − 47?

3 borrows: each time the top digit was smaller than the one below it, 1 was borrowed from the column on the left.

Why does 0 become 9 when borrowing in 1,000 − 47?

The zero has nothing to lend, so it first borrows 1 from its left neighbour and becomes 10; then it lends 1 to the column on its right and keeps 9.

See Also