LCM for 120 and 500
What's the Least Common Multiple (LCM) of 120 and 500?
(Three thousand)
Finding LCM for 120 and 500 using GCF's of these numbers
The first method to find LCM for numbers 120 and 500 is to find Greatest Common Factor (GCF) of these numbers. Here's the formula:
LCM = (Number1 × Number2) ÷ GCF
GCF of numbers 120 and 500 is 20, so
LCM = (120 × 500) ÷ 20
LCM = 60000 ÷ 20
LCM = 3000
Finding LCM for 120 and 500 by Listing Multiples
The second method to find LCM for numbers 120 and 500 is to list out the common multiples for both nubmers and pick the first which matching:
Multiples of 120: 120, 240, 360, 480, 600, 720, 840, 960, 1080, 1200, 1320, 1440, 1560, 1680, 1800, 1920, 2040, 2160, 2280, 2400, 2520, 2640, 2760, 2880, 3000, 3120, 3240
Multiples of 500: 500, 1000, 1500, 2000, 2500, 3000, 3500, 4000
So the LCM for 120 and 500 is 3000
Finding LCM for 120 and 500 by Prime Factorization
Another method to find LCM for numbers 120 and 500 is to list all Prime Factors for both numbers and multiply the highest exponent prime factors:
All Prime Factors of 120: 2, 2, 2, 3, 5 (exponent form: 23, 31, 51)
All Prime Factors of 500: 2, 2, 5, 5, 5 (exponent form: 22, 53)
23 × 31 × 53 = 3000
LCM Table
Number 1 | Number 2 | LCM |
---|---|---|
105 | 500 | 10500 |
106 | 500 | 26500 |
107 | 500 | 53500 |
108 | 500 | 13500 |
109 | 500 | 54500 |
110 | 500 | 5500 |
111 | 500 | 55500 |
112 | 500 | 14000 |
113 | 500 | 56500 |
114 | 500 | 28500 |
115 | 500 | 11500 |
116 | 500 | 14500 |
117 | 500 | 58500 |
118 | 500 | 29500 |
119 | 500 | 59500 |
120 | 500 | 3000 |
121 | 500 | 60500 |
122 | 500 | 30500 |
123 | 500 | 61500 |
124 | 500 | 15500 |
125 | 500 | 500 |
126 | 500 | 31500 |
127 | 500 | 63500 |
128 | 500 | 16000 |
129 | 500 | 64500 |
130 | 500 | 6500 |
131 | 500 | 65500 |
132 | 500 | 16500 |
133 | 500 | 66500 |
134 | 500 | 33500 |
About "Least Common Multiple" Calculator
Least Common Multiple (LCM) also known as the Lowest Common Multiple or Smallest Common Multiple of 2 numbers - it is the smallest positive integer that is divisible by both numbers