8 Choose 7

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Total items (n)
Items chosen (k)

What is 8 choose 7?

Answer

8 choose 7 is
8

Order doesn't matter, no repeats: 8 ways to choose 7 of 8 items.

Choosing 7 of 8 is the same as leaving 1 out: C(8, 7) = C(8, 1).

C(8, 7) = 8! / (7! · 1!)

= C(8, 1)

= 8 / 1

= 8

If order matters (permutations): P(8, 7) = 8 × 7 × 6 × … × 2 = 40,320 — each combination in 7! = 5,040 orders.

Row 8 of Pascal's triangle
k8 choose k
01
18
228
356
470
556
628
78
81

Row sum: 28 = 256 — all subsets of 8 items.

See Also

FAQ

What is 8 choose 7?

8 choose 7 is 8

Why is 8 choose 7 the same as 8 choose 1?

Every way to choose 7 of 8 items leaves exactly 1 behind, so choosing 7 and choosing which one to leave out are the same count: 8 choose 7 = 8 choose 1 = 8. In the formula n! / (k! (n − k)!) the two factorials below just swap places.

How many ways are there if order matters?

P(8, 7) = 40,320. Each of the 8 combinations can be put in order in 7! = 5,040 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.