15 Choose 3
Combination Calculator
What is 15 choose 3?
Answer
15 choose 3 is
455
Order doesn't matter, no repeats: 455 ways to choose 3 of 15 items.
C(15, 3) = 15! / (3! · 12!)
= (15 × 14 × 13) / (3 × 2 × 1)
= 2,730 / 6
= 455
If order matters (permutations): P(15, 3) = 15 × 14 × 13 = 2,730 — each combination in 3! = 6 orders.
| k | 15 choose k |
|---|---|
| 0 | 1 |
| 1 | 15 |
| 2 | 105 |
| 3 | 455 |
| 4 | 1,365 |
| 5 | 3,003 |
| 6 | 5,005 |
| 7 | 6,435 |
| 8 | 6,435 |
| 9 | 5,005 |
| 10 | 3,003 |
| 11 | 1,365 |
| 12 | 455 |
| 13 | 105 |
| 14 | 15 |
| 15 | 1 |
Row sum: 215 = 32,768 — all subsets of 15 items.
See Also
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n choose 3 for other n
FAQ
What is 15 choose 3?
15 choose 3 is 455
Why is 15 choose 3 the same as 15 choose 12?
Every way to choose 3 of 15 items leaves exactly 12 behind, so choosing 3 and choosing which 12 to leave out are the same count: 15 choose 3 = 15 choose 12 = 455. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
P(15, 3) = 2,730. Each of the 455 combinations can be put in order in 3! = 6 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 14 Choose 8: Combinations C(14, 8)
- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 10: Combinations C(14, 10)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- 14 Choose 13: Combinations C(14, 13)
- 14 Choose 14: Combinations C(14, 14)
- 15 Choose 0: Combinations C(15, 0)
- 15 Choose 1: Combinations C(15, 1)
- 15 Choose 2: Combinations C(15, 2)
- 15 Choose 4: Combinations C(15, 4)
- 15 Choose 5: Combinations C(15, 5)
- 15 Choose 6: Combinations C(15, 6)
- 15 Choose 7: Combinations C(15, 7)
- 15 Choose 8: Combinations C(15, 8)
- 15 Choose 9: Combinations C(15, 9)
- 15 Choose 10: Combinations C(15, 10)
- 15 Choose 11: Combinations C(15, 11)
- 15 Choose 12: Combinations C(15, 12)
- 15 Choose 13: Combinations C(15, 13)
- Число сочетаний из 15 по 3
- Combinaciones de 15 tomados de 3 en 3: C(15, 3)
- Combinação de 15 tomados 3 a 3: C(15, 3)