15 Choose 2
Combination Calculator
What is 15 choose 2?
Answer
15 choose 2 is
105
Order doesn't matter, no repeats: 105 ways to choose 2 of 15 items.
C(15, 2) = 15! / (2! · 13!)
= (15 × 14) / (2 × 1)
= 210 / 2
= 105
If order matters (permutations): P(15, 2) = 15 × 14 = 210 — each combination in 2! = 2 orders.
| k | 15 choose k |
|---|---|
| 0 | 1 |
| 1 | 15 |
| 2 | 105 |
| 3 | 455 |
| 4 | 1,365 |
| 5 | 3,003 |
| 6 | 5,005 |
| 7 | 6,435 |
| 8 | 6,435 |
| 9 | 5,005 |
| 10 | 3,003 |
| 11 | 1,365 |
| 12 | 455 |
| 13 | 105 |
| 14 | 15 |
| 15 | 1 |
Row sum: 215 = 32,768 — all subsets of 15 items.
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n choose 2 for other n
FAQ
What is 15 choose 2?
15 choose 2 is 105
Why is 15 choose 2 the same as 15 choose 13?
Every way to choose 2 of 15 items leaves exactly 13 behind, so choosing 2 and choosing which 13 to leave out are the same count: 15 choose 2 = 15 choose 13 = 105. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
P(15, 2) = 210. Each of the 105 combinations can be put in order in 2! = 2 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 14 Choose 7: Combinations C(14, 7)
- 14 Choose 8: Combinations C(14, 8)
- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 10: Combinations C(14, 10)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- 14 Choose 13: Combinations C(14, 13)
- 14 Choose 14: Combinations C(14, 14)
- 15 Choose 0: Combinations C(15, 0)
- 15 Choose 1: Combinations C(15, 1)
- 15 Choose 3: Combinations C(15, 3)
- 15 Choose 4: Combinations C(15, 4)
- 15 Choose 5: Combinations C(15, 5)
- 15 Choose 6: Combinations C(15, 6)
- 15 Choose 7: Combinations C(15, 7)
- 15 Choose 8: Combinations C(15, 8)
- 15 Choose 9: Combinations C(15, 9)
- 15 Choose 10: Combinations C(15, 10)
- 15 Choose 11: Combinations C(15, 11)
- 15 Choose 12: Combinations C(15, 12)
- Число сочетаний из 15 по 2
- Combinaciones de 15 tomados de 2 en 2: C(15, 2)
- Combinação de 15 tomados 2 a 2: C(15, 2)