14 Choose 2

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What is 14 choose 2?

Answer

14 choose 2 is
91

Order doesn't matter, no repeats: 91 ways to choose 2 of 14 items.

C(14, 2) = 14! / (2! · 12!)

= (14 × 13) / (2 × 1)
= 182 / 2

= 91

If order matters (permutations): P(14, 2) = 14 × 13 = 182 — each combination in 2! = 2 orders.

Row sum: 214 = 16,384 — all subsets of 14 items.

See Also

FAQ

What is 14 choose 2?

14 choose 2 is 91

Why is 14 choose 2 the same as 14 choose 12?

Every way to choose 2 of 14 items leaves exactly 12 behind, so choosing 2 and choosing which 12 to leave out are the same count: 14 choose 2 = 14 choose 12 = 91. In the formula n! / (k! (n − k)!) the two factorials below just swap places.

How many ways are there if order matters?

P(14, 2) = 182. Each of the 91 combinations can be put in order in 2! = 2 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.