14 Choose 2
Combination Calculator
What is 14 choose 2?
Answer
14 choose 2 is
91
Order doesn't matter, no repeats: 91 ways to choose 2 of 14 items.
C(14, 2) = 14! / (2! · 12!)
= (14 × 13) / (2 × 1)
= 182 / 2
= 91
If order matters (permutations): P(14, 2) = 14 × 13 = 182 — each combination in 2! = 2 orders.
| k | 14 choose k |
|---|---|
| 0 | 1 |
| 1 | 14 |
| 2 | 91 |
| 3 | 364 |
| 4 | 1,001 |
| 5 | 2,002 |
| 6 | 3,003 |
| 7 | 3,432 |
| 8 | 3,003 |
| 9 | 2,002 |
| 10 | 1,001 |
| 11 | 364 |
| 12 | 91 |
| 13 | 14 |
| 14 | 1 |
Row sum: 214 = 16,384 — all subsets of 14 items.
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n choose 2 for other n
FAQ
What is 14 choose 2?
14 choose 2 is 91
Why is 14 choose 2 the same as 14 choose 12?
Every way to choose 2 of 14 items leaves exactly 12 behind, so choosing 2 and choosing which 12 to leave out are the same count: 14 choose 2 = 14 choose 12 = 91. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
P(14, 2) = 182. Each of the 91 combinations can be put in order in 2! = 2 ways, so permutations = combinations × k!: P(n, k) = n! / (n − k)!.
See Also
- 13 Choose 6: Combinations C(13, 6)
- 13 Choose 7: Combinations C(13, 7)
- 13 Choose 8: Combinations C(13, 8)
- 13 Choose 9: Combinations C(13, 9)
- 13 Choose 10: Combinations C(13, 10)
- 13 Choose 11: Combinations C(13, 11)
- 13 Choose 12: Combinations C(13, 12)
- 13 Choose 13: Combinations C(13, 13)
- 14 Choose 0: Combinations C(14, 0)
- 14 Choose 1: Combinations C(14, 1)
- 14 Choose 3: Combinations C(14, 3)
- 14 Choose 4: Combinations C(14, 4)
- 14 Choose 5: Combinations C(14, 5)
- 14 Choose 6: Combinations C(14, 6)
- 14 Choose 7: Combinations C(14, 7)
- 14 Choose 8: Combinations C(14, 8)
- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 10: Combinations C(14, 10)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- Число сочетаний из 14 по 2
- Combinaciones de 14 tomados de 2 en 2: C(14, 2)
- Combinação de 14 tomados 2 a 2: C(14, 2)