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    Arccos of 1

    Arcsin, Arccos, Arctan, Arccot
    Function
    x

    What is arccos(1)?

    Answer

    arccos(1) =
    0° = 0

    Range: arccos x is an angle from 0° to 180°, so the answer is unique.

    arccos(1) is the angle α in [0°, 180°] with cos α = 1.

    cos 0° = 1 ✓

    xyOP

    α = arccos(1) = 0°

    P(cos 0°, sin 0°) = (1, 0)

    P lies on the line x = 1 in the upper half of the circle, where sin α ≥ 0; highlighted: cos α = 1.

    All four inverse functions of 1
    FunctionDegreesRadians
    arcsin(1)90°π/2
    arccos(1)0°0
    arctan(1)45°π/4
    arccot(1)45°π/4

    See Also

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    https://calculat.io/en/number/inverse-trigonometry/arccos--1Copy
    <a href="https://calculat.io/en/number/inverse-trigonometry/arccos--1">Arccos of 1 (Inverse Cosine) in Degrees and Radians</a>Copy
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    Arccos of 1 (Inverse Cosine) in Degrees and Radians. arccos(1) = 0° = 0: the angle in [0°, 180°] whose cosine is 1. With the check and the unit circle.
    https://calculat.io/en/number/inverse-trigonometry/arccos--1/generated.jpgCopy

    Arccosine of nearby values

    xarccos x
    4/5≈ 36.8699°
    √3/230° = π/6
    0.9≈ 25.8419°
    12/13≈ 22.6199°
    10° = 0
    2does not exist
    60does not exist
    Recalculate with different values ↑

    FAQ

    What is arccos(1)?

    arccos(1) = 0° = 0

    How to find arccos(1) from a table of cosines?

    Look in the table for the angle α in [0°, 180°] with cos α = 1: it is 0°, or 0 in radians.

    What is the difference between arccos, cos⁻¹ and 1/cos?

    cos⁻¹ x is another way to write arccos x (that is how the calculator key is labelled), not 1/cos x: 1/cos x is the secant. arccos x is the angle whose cosine is x; it exists only for −1 ≤ x ≤ 1. Here: arccos(1) = 0° = 0.

    See Also