15 Choose 0
Combination Calculator
What is 15 choose 0?
Answer
15 choose 0 is
1
Order doesn't matter, no repeats: 1 way to choose 0 of 15 items.
There is exactly one way: take none.
C(15, 0) = 15! / (0! · 15!)
= 1
0! = 1 (an empty product), so 15! cancels out completely.
| k | 15 choose k |
|---|---|
| 0 | 1 |
| 1 | 15 |
| 2 | 105 |
| 3 | 455 |
| 4 | 1,365 |
| 5 | 3,003 |
| 6 | 5,005 |
| 7 | 6,435 |
| 8 | 6,435 |
| 9 | 5,005 |
| 10 | 3,003 |
| 11 | 1,365 |
| 12 | 455 |
| 13 | 105 |
| 14 | 15 |
| 15 | 1 |
Row sum: 215 = 32,768 — all subsets of 15 items.
See Also
- Random Number Generator - Pick a random whole number between two bounds
- Percent to Probability Converter - Convert Percents to "1 in X" Probability Chance
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n choose 0 for other n
FAQ
What is 15 choose 0?
15 choose 0 is 1
Why is 15 choose 0 the same as 15 choose 15?
Every way to choose 0 of 15 items leaves exactly 15 behind, so choosing 0 and choosing which 15 to leave out are the same count: 15 choose 0 = 15 choose 15 = 1. In the formula n! / (k! (n − k)!) the two factorials below just swap places.
How many ways are there if order matters?
The same 1: with 0 chosen items there is only one order, so P(15, 0) = 15 choose 0 = 1. Order starts to matter from 2 items on: n × (n − 1) arrangements.
See Also
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- 14 Choose 7: Combinations C(14, 7)
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- 14 Choose 9: Combinations C(14, 9)
- 14 Choose 10: Combinations C(14, 10)
- 14 Choose 11: Combinations C(14, 11)
- 14 Choose 12: Combinations C(14, 12)
- 14 Choose 13: Combinations C(14, 13)
- 14 Choose 14: Combinations C(14, 14)
- 15 Choose 1: Combinations C(15, 1)
- 15 Choose 2: Combinations C(15, 2)
- 15 Choose 3: Combinations C(15, 3)
- 15 Choose 4: Combinations C(15, 4)
- 15 Choose 5: Combinations C(15, 5)
- 15 Choose 6: Combinations C(15, 6)
- 15 Choose 7: Combinations C(15, 7)
- 15 Choose 8: Combinations C(15, 8)
- 15 Choose 9: Combinations C(15, 9)
- 15 Choose 10: Combinations C(15, 10)
- Число сочетаний из 15 по 0
- Combinaciones de 15 tomados de 0 en 0: C(15, 0)
- Combinação de 15 tomados 0 a 0: C(15, 0)